32y^2+34y-60=0

Solution for 32y^2+34y-60=0 equation:

32y^2+34y-60=0

a = 32; b = 34; c = -60;
Δ = b2-4ac
Δ = 342-4·32·(-60)
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-94}{2*32}=\frac{-128}{64}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+94}{2*32}=\frac{60}{64}
=15/16
$